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Apr 2, 2020 at 17:01 vote accept KhashF
Mar 20, 2020 at 19:05 answer added Willie Wong timeline score: 1
Mar 20, 2020 at 18:34 comment added Willie Wong (More precisely, your function $g = \frac{x^2 + y^2}{2xy}$.)
Mar 20, 2020 at 18:29 comment added Willie Wong In your "counter example", your function $g$ is not smooth. (It is singular whenever $x = 0$ or $y = 0$.)
Mar 19, 2020 at 3:22 comment added KhashF @WillieWong Well, in that case $\omega$ is not in the form of ${\rm{d}}f$, but why not a multiple of such a thing? For instance, $\omega:=-\frac{y}{x^2+y^2}{\rm{d}}x+\frac{x}{x^2+y^2}{\rm{d}}y$ is famously closed but not exact on $U:=\Bbb{R}^2-\{(0,0)\}$. But it is a multiple of ${\rm{d}}\left(\frac{y^2}{x^2+y^2}\right)$.
Mar 19, 2020 at 3:06 comment added Willie Wong For non-examples, just take any closed but non-exact $\omega$ on $U$ that fails to be simply connected?
Mar 19, 2020 at 2:36 history asked KhashF CC BY-SA 4.0