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Mar 19, 2020 at 19:21 vote accept user267839
Mar 19, 2020 at 16:42 answer added S. Carnahan timeline score: 4
Mar 19, 2020 at 1:19 comment added Asvin Spec C[[t]] is like a formal neighborhood of the origin in the complex plane and inverting t corresponds to puncturing at the origin.
Mar 18, 2020 at 21:33 comment added user267839 @xir: a further point is that you claim that "$k((t))$ seems to have a spectrum like a punctured disk." I'm not sure what you mean at this point. It's a spectrum of a field, thus a single point, or not? In which way you interpret the spectrum of $k((t))$ to be like a punctured disc?
Mar 18, 2020 at 21:22 comment added xir i've only encountered spaces of loops, and they've been $k((t))$ points in every case for me. arcs could be different from the sound of it.
Mar 18, 2020 at 21:11 comment added user267839 by the way is for you in this context "space of loops" the same as "space of arcs"?
Mar 18, 2020 at 21:05 comment added user267839 @xir: I'm quite sure that what I'm wrote should be correct. This is my source: arxiv.org/abs/1604.02728 (see page 2). De Fernex write: "The space of arcs of $X$ is a scheme whose $K$-valued points, for any field extension $K/k$, are formal arcs $\alpha: Spec \ K[[t]] \to X$."
Mar 18, 2020 at 20:00 comment added xir are you sure that the "space of loops" isn't given by taking $k((t))$-points instead? $k((t))$ seems to have a spectrum like a punctured disk (so a loop) topologically, but $k[[t]]$ seems more like just a disk.
Mar 18, 2020 at 18:55 history edited user267839 CC BY-SA 4.0
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Mar 18, 2020 at 16:58 history asked user267839 CC BY-SA 4.0