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Mar 16, 2020 at 11:45 comment added Monty @Paul, thank you for clear explanation. I always learn much from your comment and answers!:)
Mar 15, 2020 at 15:38 comment added paul garrett Right: with a non-degenerate $E$-one-dimensional space, the corresponding unitary group has no proper parabolics... because it has no non-trivial isotropic subspaces.
Mar 15, 2020 at 5:53 comment added Monty @Paul, from your comment, I think that $U(1)$ has no proper parabolic subgroup. Right?
Mar 15, 2020 at 5:05 comment added Monty @Paul, You are right! I think there is no proper parabolic and so no proper Iwasawa decomposition. Thank you very much for comment.
Mar 14, 2020 at 21:06 comment added paul garrett Unless I misunderstand something here... $U(V_o)$ is compact, no? And has no proper ($F$-rational) parabolics.
Mar 14, 2020 at 16:09 history edited Monty CC BY-SA 4.0
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Mar 14, 2020 at 15:37 history asked Monty CC BY-SA 4.0