Timeline for Iwasawa decomposition on unitary group of anisotropic kernel
Current License: CC BY-SA 4.0
7 events
when toggle format | what | by | license | comment | |
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Mar 16, 2020 at 11:45 | comment | added | Monty | @Paul, thank you for clear explanation. I always learn much from your comment and answers!:) | |
Mar 15, 2020 at 15:38 | comment | added | paul garrett | Right: with a non-degenerate $E$-one-dimensional space, the corresponding unitary group has no proper parabolics... because it has no non-trivial isotropic subspaces. | |
Mar 15, 2020 at 5:53 | comment | added | Monty | @Paul, from your comment, I think that $U(1)$ has no proper parabolic subgroup. Right? | |
Mar 15, 2020 at 5:05 | comment | added | Monty | @Paul, You are right! I think there is no proper parabolic and so no proper Iwasawa decomposition. Thank you very much for comment. | |
Mar 14, 2020 at 21:06 | comment | added | paul garrett | Unless I misunderstand something here... $U(V_o)$ is compact, no? And has no proper ($F$-rational) parabolics. | |
Mar 14, 2020 at 16:09 | history | edited | Monty | CC BY-SA 4.0 |
added 1 character in body
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Mar 14, 2020 at 15:37 | history | asked | Monty | CC BY-SA 4.0 |