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Apr 17, 2021 at 0:52 comment added user125639 Fair enough. But is there some "a priori" estimate in terms of X in which SS(F) lives?
Apr 16, 2021 at 20:49 comment added Will Sawin @user125639 If we embed $X \subset A$ then $T^* X$ is not a subspace of $T^* A $, but rather a quotient, so the inclusion $SS(F) \subset T^* X$ would not be well-defined.
Apr 16, 2021 at 20:12 comment added user125639 @WillSawin, do you know if the containment $SS(F) \subset T^*X$ holds in the singular case?
Mar 14, 2020 at 0:06 comment added Will Sawin For $f: X \to Y$ proper, embed $X$ into $A$, embed $Y$ into $B$, and then embed $X$ into $A \times B$ diagonally via $f$. This works fine if $X$ and $Y$ are quasiprojective, I think. I agree it's beneficial to have a general theory though.
Mar 13, 2020 at 23:57 comment added prochet the drawback of such a definition is for instance if one would have functoriality w.r.t to proper morphisms, because there is no reason that it extends to the embedding.
Mar 13, 2020 at 16:05 comment added Will Sawin Won't any two embeddings of the same dimension be locally equivalent in the analytic or etale topology? Independence should follow from that.
Mar 12, 2020 at 7:51 history asked prochet CC BY-SA 4.0