Timeline for Are triangulations of n-dimensional manifolds determined by lower-dimensional skeleta?
Current License: CC BY-SA 4.0
5 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Mar 6, 2020 at 16:58 | history | edited | Moishe Kohan | CC BY-SA 4.0 |
added 445 characters in body
|
Mar 6, 2020 at 4:48 | comment | added | Moishe Kohan | @RichardStanley: Interesting. This means that $k(d-1)\ge [d/2]$, at least if $d$ is high enough. I will have to read more about this counting result. | |
Mar 6, 2020 at 0:28 | comment | added | Richard Stanley | There are superexponentially many (in both $n$ and $d$) triangulations of a $(d-1)$-dimensional sphere (or even a simplicial $d$-polytope) with $n$ vertices such that every $\lfloor d/2 \rfloor$-element set of vertices form a face. On the other hand, if every ($\lfloor d/2\rfloor +1$)-element set of vertices form a face, then $n=d+1$ and the triangulation has just one maximal face. See en.wikipedia.org/wiki/Neighborly_polytope. Some results are also known for other manifolds. | |
Mar 5, 2020 at 23:59 | history | edited | Moishe Kohan | CC BY-SA 4.0 |
edited title
|
Mar 5, 2020 at 23:41 | history | asked | Moishe Kohan | CC BY-SA 4.0 |