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Mar 5, 2020 at 16:34 comment added Bazin Thanks, that's great. Some minor remarks on your two last paragraphs. Let's call $\mathcal H=\{(x,y)\in \mathbb R^2, y\ge \sqrt{x^2+1}\}$. Indeed we have $\mathcal H\subset\{P\le 0\}$ for your reason (1) and also $\mathcal H^c\subset\{P\ge 0\}$
Mar 4, 2020 at 22:22 history answered Dmitri Panov CC BY-SA 4.0