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Mar 16, 2020 at 9:33 history bounty ended CommunityBot
Mar 10, 2020 at 1:58 history edited Aaron Meyerowitz CC BY-SA 4.0
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Mar 9, 2020 at 21:10 history bounty ended CommunityBot
Mar 2, 2020 at 8:37 comment added user153000 Luckily, I have not.
Mar 1, 2020 at 23:49 comment added Brendan McKay @StanTuwim That's interesting. Do you find examples that beat Aaron's records?
Mar 1, 2020 at 23:20 comment added user153000 I don't think that last remark - changing $01$ with $10$ - is true. I have been checking best binary sequences with fixed number of ones and the maximisers are not always $111...000$ or $000...111$.
Mar 1, 2020 at 23:04 comment added Brendan McKay This conjecture is correct up to 13 vertices. If the focus on threshold graphs is solid, using the representation of a threshold graph as a binary string (0 for add an isolated vertex, 1 for add a new vertex joined to everything so far) might be the way to go. I think that the effect of changing 01 to 10 in the string is simple. But I stopped working on it so feel free ;).
Mar 1, 2020 at 22:55 history edited Aaron Meyerowitz CC BY-SA 4.0
added 370 characters in body
Mar 1, 2020 at 18:01 comment added user153000 I agree, in my opinion this should be a maximizer. But it must somehow depend on power $3$. For $1$ instead of $3$ we get so called "total irregularity index" and maximizer turns out to be different...
Mar 1, 2020 at 1:40 history answered Aaron Meyerowitz CC BY-SA 4.0