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S Mar 18, 2020 at 14:37 history suggested RobPratt CC BY-SA 4.0
added \deg and corrected typo
Mar 18, 2020 at 14:35 review Suggested edits
S Mar 18, 2020 at 14:37
S Mar 16, 2020 at 9:33 history bounty ended CommunityBot
S Mar 16, 2020 at 9:33 history notice removed user153000
S Mar 9, 2020 at 21:11 history bounty started CommunityBot
S Mar 9, 2020 at 21:11 history notice added user153000 Improve details
S Mar 9, 2020 at 21:10 history bounty ended CommunityBot
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Mar 4, 2020 at 19:51 comment added user153000 It is proven here: books.google.pl/…
Mar 4, 2020 at 19:47 comment added user153000 This index $\mathcal{I_{n}}$ is a convex function of degree sequence $\mathcal {deg}x_{1},...,\mathcal{deg}x_{n}$. Call the set of all such graphic sequences $D$. Then we can look on $D^{*}=\mathcal{Con}D$ - a convex hull of $D$. $I_{n}$ must then attain it's maximum on some extreme point of $D^{*}$. It can be shown, that such extreme points of $D^{*}$ are exactly those corresponding to threshold graphs.
Mar 4, 2020 at 19:09 comment added Aaron Meyerowitz How do you get that the maximum occurs for threshold graphs? I'm not doubting it but don't see it so I am just wondering how you would show it.
S Mar 2, 2020 at 23:36 history bounty started CommunityBot
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Mar 1, 2020 at 1:40 answer added Aaron Meyerowitz timeline score: 4
Feb 29, 2020 at 16:58 comment added Martin Rubey Divisibility by $4$ is easy (but tedious) to show by induction on the number of edges.
Feb 29, 2020 at 15:46 comment added Martin Rubey actually, dmtcs.episciences.org/1263 considers your invariant with $3:=1$, which might be helpful.
Feb 29, 2020 at 15:41 comment added Martin Rubey The "Albertson index" is a bit similar, see findstat.org/St001350
Feb 29, 2020 at 15:36 comment added Martin Rubey Is it obvious that this number is always divisible by four - for any value of 3?
Feb 29, 2020 at 13:30 review First posts
Feb 29, 2020 at 13:40
Feb 29, 2020 at 13:26 history asked user153000 CC BY-SA 4.0