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Oct 26, 2020 at 10:23 vote accept ManUtdBloke
Mar 4, 2020 at 11:15 answer added Jochen Glueck timeline score: 4
Mar 1, 2020 at 13:00 comment added ManUtdBloke @KeithMcClary I have seen Pade approximants mentioned in the context of accelerating the convergence a Neumann series but I didn't know they can also work when a Neumann series doesn't converge. So I'll take a look into this, although I am dealing with non-symmetric operators so maybe it can't be applied to my case.
Mar 1, 2020 at 12:53 history edited ManUtdBloke CC BY-SA 4.0
edited body
Mar 1, 2020 at 5:52 answer added Robert Israel timeline score: 4
Feb 29, 2020 at 22:48 comment added Keith McClary For symmetric operators Hilbert Space and the Padé Approximant, non-paywalled Google Books preview starting p.197 . Not a "series representation".
Feb 29, 2020 at 20:09 comment added Yemon Choi BTW you have $I+A$ at one point and $I-A$ on the next line; I assume one of these is a typo?
Feb 29, 2020 at 20:08 comment added Yemon Choi You would still win if the spectral radius of $A$ is less than $1$. If the spectral radius of $A$ is $\geq 1$ then $I$ might be in the spectrum of $A$ and then there is no hope of defining $(I-A)^{-1}$ as a bounded operator
Feb 29, 2020 at 16:24 history edited YCor CC BY-SA 4.0
fixed title, minor formatting
Feb 29, 2020 at 12:41 history asked ManUtdBloke CC BY-SA 4.0