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Feb 27, 2020 at 20:23 comment added LSpice @FredRohrer, the problems is what kind of object $K^n$ is—or, perhaps to phrase it differently, how many automorphisms we allow it. As a bare vector space (with a full $\operatorname{GL}_n(K)$ of automorphisms), it's probably not reasonable to call the standard basis canonical, since it's not preserved by automorphisms. As a product of copies of $K$ indexed by the cardinal $n$, it has no non-trivial automorphisms, and the standard basis can reasonably be identified as a canonical choice. Bourbaki is careful, but can still make mistakes, or—if that is too strong—infelicities.
Feb 27, 2020 at 20:15 comment added Fred Rohrer Well, Bourbaki, who is known for careful use of words, writes canonical basis for what you call standard basis.
Feb 27, 2020 at 20:11 history edited anon CC BY-SA 4.0
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Feb 27, 2020 at 20:05 history answered anon CC BY-SA 4.0