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Feb 25, 2020 at 21:38 comment added Mateusz Kwaśnicki If $f_n(t) = \sin(n t)$ and $f(t) = 0$, then the left-hand side is $n/(\lambda^2 + n^2)$, which is $O(1/n)$ despite the fact that $f_n(t)$ does not converge to $f(t)$ pointwise. Or am I missing something?
Feb 25, 2020 at 15:06 history asked Wenguang Zhao CC BY-SA 4.0