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Mar 1, 2020 at 22:58 vote accept Johannes Hahn
Mar 1, 2020 at 19:35 answer added bl' timeline score: 4
Feb 23, 2020 at 15:13 comment added Johannes Hahn Just as you'd think: $Out(A) := Aut_{k\text{-Alg}}(A) / Inn(A)$ where $Inn(A)$ is the normal subgroup consisting of automorphisms that are of the form $a\mapsto uau^{-1}$ for some unit $u\in A^\times$.
Feb 22, 2020 at 22:31 comment added YCor Would you recall how Out of a $k$-algebra is defined?
Feb 22, 2020 at 22:25 history edited Johannes Hahn CC BY-SA 4.0
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Feb 22, 2020 at 22:17 history asked Johannes Hahn CC BY-SA 4.0