Timeline for Uniqueness of maximal subfields
Current License: CC BY-SA 2.5
3 events
| when toggle format | what | by | license | comment | |
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| Aug 12, 2010 at 18:16 | comment | added | Skip | I meant "not isomorphic as $Z$-algebras" (which is obvious because $b$ is not a square in $Z$); I agree they are isomorphic as $F$-algebras. I think $Z$-algebra isomorphism is what was intended in the original question. | |
| Aug 12, 2010 at 14:56 | comment | added | George McNinch | Why is the field $Z(\sqrt{a})$ not isomorphic to $Z(\sqrt{ab})$? In fact, I believe those fields are isomorphic as $F$-algebras (though not as $Z$-algebras), since $Z = F(a,b) = F(ab,b)$. | |
| Aug 11, 2010 at 20:16 | history | answered | Skip | CC BY-SA 2.5 |