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David White
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If A is a commutative algebra and B is an X- algebra, then the tesnortensor product $A \otimes B$ is an X-algebra (so for example, $Com \otimes Lie$ is a Lie algebra). This is seen using the language of operads. Let Com$Com$ be the commutative operad. Since Com(n)$Com(n)$ is a one dimensional vector space for every n$n$, tensoring Com$Com$ with an operad O$O$ doesn't change the operad O$O$.

Does a similar thing hold true for a C-infinity$C_\infty$ algebra? That is, if A$A$ is a $C_\infty$ algebra, is $A \otimes B$ an $X_\infty$ algebra?

I'm still trying to familiarize myself with the language of operads, and perhaps the question can be made more precise in that language, where the infinity version of an operad is cofibrant resolution of the operad.

If A is a commutative algebra and B is an X- algebra, then the tesnor product $A \otimes B$ is an X-algebra (so for example, $Com \otimes Lie$ is a Lie algebra). This is seen using the language of operads. Let Com be the commutative operad. Since Com(n) is a one dimensional vector space for every n, tensoring Com with an operad O doesn't change the operad O.

Does a similar thing hold true for a C-infinity algebra? That is, if A is a $C_\infty$ algebra, is $A \otimes B$ an $X_\infty$ algebra?

I'm still trying to familiarize myself with the language of operads, and perhaps the question can be made more precise in that language, where the infinity version of an operad is cofibrant resolution of the operad.

If A is a commutative algebra and B is an X- algebra, then the tensor product $A \otimes B$ is an X-algebra (so for example, $Com \otimes Lie$ is a Lie algebra). This is seen using the language of operads. Let $Com$ be the commutative operad. Since $Com(n)$ is a one dimensional vector space for every $n$, tensoring $Com$ with an operad $O$ doesn't change the operad $O$.

Does a similar thing hold true for a $C_\infty$ algebra? That is, if $A$ is a $C_\infty$ algebra, is $A \otimes B$ an $X_\infty$ algebra?

I'm still trying to familiarize myself with the language of operads, and perhaps the question can be made more precise in that language, where the infinity version of an operad is cofibrant resolution of the operad.

added 5 characters in body; edited body
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Micah Miller
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If A is a commutative algebra and B is an X- algebra, then the tesnor product $A \otimes X$$A \otimes B$ is an X-algebra for any algebra X (so for example, $Com \otimes Lie$ is a Lie algebra). This is seen using the language of operads. Let Com be the commutative operad. Since Com(n) is a one dimensional vector space for every n, tensoring Com with an operad O doesn't change the operad O.

Does a similar thing hold true for a C-infinity algebra? That is, if A is a $C_\infty$ algebra, is $A \otimes X$$A \otimes B$ an $X_\infty$ algebra?

I'm still trying to familiarize myself with the language of operads, and perhaps the question can be made more precise in that language, where the infinity version of an operad is cofibrant resolution of the operad.

If A is a commutative algebra, then the tesnor product $A \otimes X$ is an X-algebra for any algebra X (so for example, $Com \otimes Lie$ is a Lie algebra). This is seen using the language of operads. Let Com be the commutative operad. Since Com(n) is a one dimensional vector space for every n, tensoring Com with an operad O doesn't change the operad O.

Does a similar thing hold true for a C-infinity algebra? That is, if A is a $C_\infty$ algebra, is $A \otimes X$ an $X_\infty$ algebra?

I'm still trying to familiarize myself with the language of operads, and perhaps the question can be made more precise in that language, where the infinity version of an operad is cofibrant resolution of the operad.

If A is a commutative algebra and B is an X- algebra, then the tesnor product $A \otimes B$ is an X-algebra (so for example, $Com \otimes Lie$ is a Lie algebra). This is seen using the language of operads. Let Com be the commutative operad. Since Com(n) is a one dimensional vector space for every n, tensoring Com with an operad O doesn't change the operad O.

Does a similar thing hold true for a C-infinity algebra? That is, if A is a $C_\infty$ algebra, is $A \otimes B$ an $X_\infty$ algebra?

I'm still trying to familiarize myself with the language of operads, and perhaps the question can be made more precise in that language, where the infinity version of an operad is cofibrant resolution of the operad.

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Micah Miller
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Extending a property of commutative algebras to C infinity algebras

If A is a commutative algebra, then the tesnor product $A \otimes X$ is an X-algebra for any algebra X (so for example, $Com \otimes Lie$ is a Lie algebra). This is seen using the language of operads. Let Com be the commutative operad. Since Com(n) is a one dimensional vector space for every n, tensoring Com with an operad O doesn't change the operad O.

Does a similar thing hold true for a C-infinity algebra? That is, if A is a $C_\infty$ algebra, is $A \otimes X$ an $X_\infty$ algebra?

I'm still trying to familiarize myself with the language of operads, and perhaps the question can be made more precise in that language, where the infinity version of an operad is cofibrant resolution of the operad.