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Feb 14, 2020 at 3:09 vote accept Powerspawn
Feb 14, 2020 at 2:40 answer added Zach Teitler timeline score: 4
Feb 14, 2020 at 1:03 comment added Igor Rivin Answered here? math.stackexchange.com/questions/428205/…
Feb 13, 2020 at 23:55 comment added Abdelmalek Abdesselam oops you're right got mixed up between what is dimension and what is codimension
Feb 13, 2020 at 23:49 comment added Powerspawn @AbdelmalekAbdesselam The hyperplanes have codimension $1$, so each intersection reduces the dimension of $V$ by $1$, so we need to intersect with $d$ hyperplanes total.
Feb 13, 2020 at 23:43 comment added Abdelmalek Abdesselam you mean $n-d$ hyperplanes
Feb 13, 2020 at 23:36 comment added Powerspawn The definition I'm using is that if $V$ has dimension $d$, then the degree of $V$ is equal to the number of intersection point of $V$ with $d$ hyperplanes in general position. (Including intersections at infinity and intersection multiplicity).
Feb 13, 2020 at 23:32 comment added YCor How do you define the degree of $V$ of $V$ is not a hypersurface?
Feb 13, 2020 at 23:30 review First posts
Feb 14, 2020 at 0:23
Feb 13, 2020 at 23:29 history asked Powerspawn CC BY-SA 4.0