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Feb 13, 2020 at 16:06 comment added F. Carbon @user131781 this is a very useful comment, thank you very much!
Feb 13, 2020 at 15:56 vote accept F. Carbon
Feb 13, 2020 at 15:45 comment added user131781 This is just an addendum to Dirk Werner’s definitive answer but it might add useful information: every Banach space is isometrically isomorphic to a subspace of a $C(K)$-space (even $C([0,1])$ if separable) so there is no point in examining special properties of the latter if they are inherited by subspaces.
Feb 13, 2020 at 15:14 answer added Dirk Werner timeline score: 5
Feb 13, 2020 at 14:28 comment added F. Carbon @DirkWerner Thank you very much for this comment, so this means I could not find it in the books as the answer is trivial (to somebody who knows more functional analysis than I do...). If you want you could extend your comment to an answer and I will accept it.
Feb 13, 2020 at 13:03 comment added Dirk Werner It is known that $C(K)$, for infinite $K$, contains a copy of $c_0$, hence it does not have nontrivial type (meaning $>1$) or nontrivial cotype (meaning $<\infty$).
Feb 13, 2020 at 12:24 history asked F. Carbon CC BY-SA 4.0