Skip to main content
deleted 3 characters in body
Source Link
Alexandre Eremenko
  • 91.8k
  • 9
  • 259
  • 429

The inverse map satisfies $|\phi^{-1}(z)-\phi^{-1}(a)|\leq c|z-a|^{n/(n-2)}$ at any vertex $a$ (reciprocal to the exponent of the direct map). Since this the exponent exponent is $>1$ the inverse is just Lipschitz everywhere. You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

The inverse map satisfies $|\phi^{-1}(z)-\phi^{-1}(a)|\leq c|z-a|^{n/(n-2)}$ at any vertex $a$ (reciprocal to the exponent of the direct map). Since this the exponent is $>1$ the inverse is just Lipschitz everywhere. You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

The inverse map satisfies $|\phi^{-1}(z)-\phi^{-1}(a)|\leq c|z-a|^{n/(n-2)}$ at any vertex $a$ (reciprocal to the exponent of the direct map). Since this exponent is $>1$ the inverse is just Lipschitz everywhere. You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

added 65 characters in body
Source Link
Alexandre Eremenko
  • 91.8k
  • 9
  • 259
  • 429

The inverse map is Hölder with exponentsatisfies $n/(n-2)$$|\phi^{-1}(z)-\phi^{-1}(a)|\leq c|z-a|^{n/(n-2)}$ at any vertex $a$ (reciprocal to the exponent of the direct map). Since this the exponent is $>1$ the inverse is just Lipschitz everywhere. You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

The inverse map is Hölder with exponent $n/(n-2)$ (reciprocal to the exponent of the direct map). You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

The inverse map satisfies $|\phi^{-1}(z)-\phi^{-1}(a)|\leq c|z-a|^{n/(n-2)}$ at any vertex $a$ (reciprocal to the exponent of the direct map). Since this the exponent is $>1$ the inverse is just Lipschitz everywhere. You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

minor typo
Source Link
Martin Sleziak
  • 4.7k
  • 4
  • 35
  • 40

The inverse map is HilderHölder with exponent $n/(n-2)$ (reciprocal to the exponent of the direct map). You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

The inverse map is Hilder with exponent $n/(n-2)$ (reciprocal to the exponent of the direct map). You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

The inverse map is Hölder with exponent $n/(n-2)$ (reciprocal to the exponent of the direct map). You do not need any general theorems for this. At the vertex the inverse map behaves like a power. At all other points it is smooth (analytic).

Source Link
Alexandre Eremenko
  • 91.8k
  • 9
  • 259
  • 429
Loading