Timeline for A numerical calculation for an integral
Current License: CC BY-SA 4.0
10 events
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| Feb 13, 2020 at 16:05 | comment | added | Bazin | Thanks a lot for caring to check this; of course I renew my thanks for your very helpful and thorough answer to my question. | |
| Feb 13, 2020 at 10:42 | comment | added | Carlo Beenakker | you are right, it was my typing error, apologies for the confusion. | |
| Feb 13, 2020 at 10:42 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Feb 13, 2020 at 10:31 | comment | added | Bazin | Sorry to bother you again with that matter. I would be very grateful if you could double-check your constant $\sqrt{2\pi}$, which I believe should be replaced by $\sqrt{2/\pi}$. Thanks. | |
| Feb 11, 2020 at 12:40 | comment | added | Bazin | In your asymptotic expression, it seems that the term $\sqrt{2π}$ should be replaced by $\sqrt{2/π}$. | |
| Feb 11, 2020 at 9:14 | comment | added | Bazin | Great! Thank you very much. | |
| Feb 10, 2020 at 20:35 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Feb 10, 2020 at 20:15 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Feb 10, 2020 at 20:09 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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| Feb 10, 2020 at 20:03 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |