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Feb 19, 2020 at 9:14 answer added Denis Serre timeline score: 1
Feb 11, 2020 at 13:07 vote accept Jochen Glueck
Feb 10, 2020 at 22:38 answer added Abdelmalek Abdesselam timeline score: 4
Feb 10, 2020 at 22:07 answer added Francois Ziegler timeline score: 6
Feb 10, 2020 at 16:43 comment added Jochen Glueck @FrancoisZiegler: Thank you very much for the references! (I particularly like the first one.) If you post the reference as an answer, I'll certainly accept it.
Feb 10, 2020 at 16:42 comment added Jochen Glueck @JohannesHahn: Thank you for your comment! I agree that one can probably show the formula by concretely computing some integrals. The major motivation of my question though was not to look for an alternative proof (probably the original wording of the question was somewhat misleading, and suggested that I was looking for a simpler or less "lengthy" proof). The main reason for my reference request was that I was wondering in which contexts this formula might occur in the literature.
Feb 9, 2020 at 23:33 comment added Johannes Hahn If I'm not mistaken then it's also possible to use the coarea formula to rewrite the integral over $S^{2n-1}$ into a double integral over the unit disk and $S^{2n-3}$. An induction over $n$ then should do the trick. Alternatively: Pick a basis and do everything in coordinates. But this might be "lengthy" again.
Feb 9, 2020 at 23:33 history edited Jochen Glueck CC BY-SA 4.0
deleted 42 characters in body
Feb 9, 2020 at 23:31 comment added Jochen Glueck @FrancoisZiegler: Well, it's precisely the computation of those two scalars that took me a page or two. But admittedly, "lengthy" might be a bit of an exagaration. I think I'll better remove this word from the post.
Feb 9, 2020 at 22:36 history edited Jochen Glueck CC BY-SA 4.0
Fixed a typo in the integral representation formula.
Feb 9, 2020 at 21:50 history asked Jochen Glueck CC BY-SA 4.0