Timeline for Is it true that exotic smooth R^4 cannot be diffeomorphic to RxN, where N is a 3-manifold?
Current License: CC BY-SA 2.5
6 events
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| Aug 14, 2010 at 20:25 | history | edited | Torsten Asselmeyer-Maluga | CC BY-SA 2.5 |
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| Aug 14, 2010 at 20:19 | comment | added | Torsten Asselmeyer-Maluga | Yes, you are right but I was not sure. I edited the answer. Thanks for the comment. | |
| Aug 13, 2010 at 15:39 | comment | added | Andy Putman | I don't understand this answer. Why do you need a fancy theorem to conclude that an exotic $\mathbb{R}^4$ is homeomorphic to a standard $\mathbb{R}^4$? Isn't that the definition? | |
| Aug 13, 2010 at 13:29 | history | edited | Torsten Asselmeyer-Maluga | CC BY-SA 2.5 |
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| Aug 12, 2010 at 7:41 | history | edited | Torsten Asselmeyer-Maluga | CC BY-SA 2.5 |
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| Aug 11, 2010 at 10:42 | history | answered | Torsten Asselmeyer-Maluga | CC BY-SA 2.5 |