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Feb 7, 2020 at 18:08 vote accept M.L
Feb 7, 2020 at 17:42 answer added Giorgio Metafune timeline score: 3
Feb 7, 2020 at 17:39 comment added Giorgio Metafune Ok, I will do. I was not sure about the question.
Feb 7, 2020 at 17:20 comment added Nik Weaver @GiorgioMetafune: I think it's worth posting this as an answer.
Feb 7, 2020 at 15:02 comment added Giorgio Metafune If I understood correctly the question, this is not true. If $u_n(t,x)=\sin (2\pi n\, t)f(x)$ for a fixed $f \neq 0$, then $u_n \to 0$, $w^*$ in $(t,x)$ by Riemann Lebesgue, but for fixed $t\neq 0,1/2,1$ does not converge $w^*$ in $x$. Similarly, there is no way to find a sequence $n_j$ such that $\sin (n_j t)$ converges a.e. Positivity does not help: tafe $f$ positive and add 1 to the sinus.
Feb 7, 2020 at 10:41 history asked M.L CC BY-SA 4.0