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Feb 7, 2020 at 15:28 comment added Willie Wong In the paper you cite there are only two principle stretches, and so their squares solve the characteristic equation for the square $F^* F$ (which is two-by-two). So in particular you can use the quadratic equation to write down $\lambda_*$ as algebraic expressions in terms of $F$ and find the derivatives directly. (This is the equation 6.2 in that paper) // In the $3\times 3$ case I guess you can try using the cubic formula....
Feb 7, 2020 at 15:22 comment added Willie Wong Isn't this, by the chain rule, mainly an issue of computing $\partial \lambda_* / \partial F$?
Feb 7, 2020 at 2:38 history asked msaBU CC BY-SA 4.0