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Feb 8, 2020 at 10:44 vote accept nowhere dense
Feb 7, 2020 at 13:19 comment added Dario Spirito I'm not sure. For algebras of finite type probably one can try by induction (if $K=\mathrm{Frac}(A)=F[x_1,\ldots,x_n]$, restrict everything to $F[x_1,\ldots,x_{n-1}]$, then to $F[x_1,\ldots.x_{n-2}], etc.: all dimensions should decrease by 1 each time), but I haven't worked it out. I also feel there should be an easier proof for arbitrary Noetherian rings.
Feb 6, 2020 at 12:04 comment added nowhere dense Thanks, that is really interesting! Do you have any idea of what will happen when $A$ is an algebra of finite type over a field? In this case by Abhyankar's inequality the rational rank, and hence the rank, is bounded by the krull dimension of $A$, so we can't have the same type of obstruction.
Feb 6, 2020 at 10:47 history answered Dario Spirito CC BY-SA 4.0