Skip to main content
4 events
when toggle format what by license comment
Feb 3, 2020 at 18:55 comment added Dmitri Pavlov @MortyPB: A natural transformation F→G (in our case, F=G//G→*→G//G and G=id) is a collection of morphisms F(X)→G(X) that satisfies a certain commutativity condition. The data of morphisms F(X)→G(X) is uniquely prescribed because we already know F(X) and G(X) and there is exactly one morphism of the form F(X)→G(X). Likewise, any square diagram (in fact, any diagram) in G//G automatically commutes because any pair of morphisms between the same objects coincides.
Feb 3, 2020 at 16:39 comment added user267839 Could you lose few words on your last argument that the composition G//G→*→G//G is homotopic to identity "via the unique choices of morphisms in G//G". I not fully understand what you mean. By constuction between every $g,h \in G//G$ there exist exactly one map. Why does this imply the desired claim?
Feb 3, 2020 at 16:32 vote accept user267839
Feb 3, 2020 at 3:22 history answered Dmitri Pavlov CC BY-SA 4.0