Timeline for Naive generalization of determinant from matrices to higher rank tensors
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| Feb 3, 2020 at 10:01 | comment | added | Oscar Cunningham | One interesting property is that this determinant is $0$ when the tensors have an odd number of indices. | |
| Feb 3, 2020 at 9:08 | comment | added | Weather Report | @MoritzEissler Thanks for the link! The question there is indeed the same, but the answer just states the formula from my post without giving it a name of explaining why is that a good definition. Another suggestion was to check out hyperdeterminant, but as far as I can see it is different from my formula. | |
| Feb 2, 2020 at 22:51 | comment | added | Moritz | math.stackexchange.com/q/1213130 Hey! This might be exactly what you're looking for :) | |
| Feb 2, 2020 at 19:52 | history | asked | Weather Report | CC BY-SA 4.0 |