Timeline for Real Rank of $M_n(A)$
Current License: CC BY-SA 4.0
3 events
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Jan 31, 2020 at 10:28 | comment | added | Hannes Thiel | Yes, one can handle specific cases of low rank. If rr(A)=0, then rr(M_n(A))=0. If rr(A)=1 and sr(A)=1, then sr(M_n(A))=1 and thus rr(M_n(A))\leq 1 (and actually =1), But even the general case of rr(A)=1 is not clear to me. | |
Jan 30, 2020 at 16:21 | comment | added | Manny Reyes | You are almost surely aware of this, but the answer is known to be affirmative in case $\mathrm{rr}(A) = 0$ by Theorem 2.10 in Brown & Pedersen. | |
Jan 30, 2020 at 10:55 | history | asked | Hannes Thiel | CC BY-SA 4.0 |