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Feb 1, 2020 at 20:52 comment added Todd Trimble I'd say there's no question this meets the cuteness criterion.
Jan 31, 2020 at 4:53 comment added Noam D. Elkies As it stands such an argument would prove it only for integers $a>0$ — but that's enough because for each $n$ the equality of $x^n$ coefficients is a polynomial identity in $a$.
Jan 29, 2020 at 19:13 history answered Marcus M CC BY-SA 4.0