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Jan 30, 2020 at 13:58 history edited Will Brian CC BY-SA 4.0
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Jan 30, 2020 at 13:57 comment added Will Brian @RobertFurber: You're perfectly right, of course. A perfectly normal space is a normal space in which every closed set is $G_\delta$. (I was thinking of this whole problem in the context of normal spaces, but apparently that's not clear. I'll edit to make it clear.)
Jan 30, 2020 at 3:03 comment added Robert Furber In the the Moore plane/Niemytskii plane every closed set is $G_\delta$, but it is not normal. Call me old-fashioned, but I think "perfectly normal" should imply "normal". It is true, via a proof using Urysohn's lemma countably many times and carefully summing up the resulting functions, that a perfectly normal space is the same thing as a normal space in which every closed set is $G_\delta$. Of course, this does not affect the argument for the lexicographic ordering not being normal, because only the direction "perfectly normal $\Rightarrow$ all closed sets are $G_\delta$" is used.
Jan 29, 2020 at 12:54 comment added Will Brian @NateEldredge: Good observation! It's not exactly using a nuke to kill a fly, but it is using more than just the flyswatter. I've edited to simplify things.
Jan 29, 2020 at 12:53 history edited Will Brian CC BY-SA 4.0
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Jan 28, 2020 at 16:58 vote accept VDGG
Jan 28, 2020 at 16:58 vote accept VDGG
Jan 28, 2020 at 16:58
Jan 28, 2020 at 15:54 comment added Nate Eldredge Just to note a slight variation (since I had been thinking about a similar proof before I saw yours): the complement of $A_U$ is actually at most countable, since every point of it is isolated in the usual topology of $[0,1]$. So any $G_\delta$ containing $C$ must in fact contain co-countably many vertical lines, and you don't need Baire.
Jan 28, 2020 at 15:51 comment added Nate Eldredge I think you missed one: "horizontal line" at the end should be "vertical line"?
Jan 28, 2020 at 15:48 history edited Will Brian CC BY-SA 4.0
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Jan 28, 2020 at 15:44 vote accept VDGG
Jan 28, 2020 at 16:58
Jan 28, 2020 at 15:27 history answered Will Brian CC BY-SA 4.0