Timeline for Tauberian operators
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 7, 2020 at 18:20 | comment | added | mahamed-beghdadi | Please, a nother quetion Mr. Gonzalez. If $(x_n ^{**}) \in l_2 (X^{**})$ and $(x_n^{**}) \in X$, then $(x_n ^{**}) \in l_2 (X^{**}) \cap X $. How to conclude that $(x_n ^{**}) \in l_2 (X)$. | |
| Jan 22, 2020 at 20:37 | vote | accept | mahamed-beghdadi | ||
| Jan 22, 2020 at 9:40 | history | edited | M.González | CC BY-SA 4.0 |
improved exposition
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| Jan 22, 2020 at 9:20 | comment | added | M.González | $(x_n^{**}/n)\in \ell_2(X)\Rightarrow x_n^{**}\in X$ for each $n$. Moreover $(x_n^{**})\in \ell_2(X^{**})$ and $x_n^{**}\in X$ for each $n$ implies $(x_n^{**})\in \ell_2(X)$. | |
| Jan 22, 2020 at 8:46 | comment | added | mahamed-beghdadi | We have $\frac{x_n^{**}}{n} \in l_2(X) $, then $\sum|| \frac{x_n^{**}}{n}||^{2} < \infty $. Taking account that $\sum|| \frac{x_n^{**}}{n}||^{2} \leq \sum|| x_n^{**}||^{2}$, so perhaps $\sum|| x_n^{**}||^{2}=\infty$. | |
| Jan 22, 2020 at 8:20 | history | answered | M.González | CC BY-SA 4.0 |