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Jun 15, 2020 at 7:27 history edited CommunityBot
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Jan 23, 2020 at 11:35 vote accept Ivan Di Liberti
Jan 23, 2020 at 11:33 answer added Martin Brandenburg timeline score: 3
Jan 23, 2020 at 10:43 comment added Martin Brandenburg One doesn't need monads to understand Kelly's tensor product. Q3 is probably answered in core.ac.uk/download/pdf/82548027.pdf
Jan 21, 2020 at 22:09 comment added Ivan Di Liberti Looking a bit closer to the paper, the fact that everything is strict might be a problem in this case. Maybe this is fixable, I will think about it.
Jan 21, 2020 at 21:57 comment added Ivan Di Liberti Thank you very much! I remember John mentioned me the paper of Hyland and Power, but he did not mention to me his own paper! I think this might really be an answer to my question!
Jan 21, 2020 at 21:04 comment added Noam Zeilberger @IvanDiLiberti have you seen Bourke's paper on Skew structures in 2-category theory and homotopy theory? Section 6 discusses a 2-dimensional version of Kock's result due to Hyland and Power, which Bourke argues is nicely analyzed via a skew closed structure on the 2-category $T\text{-}\mathrm{Alg}_s$ of algebras and strict morphisms.
Jan 21, 2020 at 17:59 answer added Giorgio Mossa timeline score: 4
Jan 21, 2020 at 17:51 history edited Ivan Di Liberti CC BY-SA 4.0
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Jan 21, 2020 at 17:31 comment added Ivan Di Liberti @SimonHenry, I hope I finally managed to give a good reference. Seal does not show that it is monoidal closed, because he does not assume closedness of the base, yet he proves monoidality of the Eilenberg-More category of algebras. No assumption on presentability is needed. I believe that if the base is closed, so is the EM-category.
Jan 21, 2020 at 17:29 history edited Ivan Di Liberti CC BY-SA 4.0
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Jan 21, 2020 at 17:04 history edited Ivan Di Liberti CC BY-SA 4.0
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Jan 21, 2020 at 17:02 comment added Simon Henry I think the reference you gave only show that the category of algebra is a "closed category", it does not show it is monoidal. I will be tempted to think that to get a monoidal category of algebras you need some presentabitliy/accessibility assumption, or at least cocompletness. In the case of interest to you this result only gave you that functor categories are $\mathcal{F}$-cocomplete, which you already know.
Jan 21, 2020 at 16:49 comment added Ivan Di Liberti @SimonHenry, thanks. I edited.
Jan 21, 2020 at 16:49 history edited Ivan Di Liberti CC BY-SA 4.0
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Jan 21, 2020 at 16:28 comment added Simon Henry Could you give a reference for Kock's results ? he has several paper on strong & commutative monads and I can't find the one where this theorem is...
Jan 21, 2020 at 15:41 history edited Ivan Di Liberti CC BY-SA 4.0
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Jan 21, 2020 at 14:46 history edited Ivan Di Liberti CC BY-SA 4.0
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Jan 21, 2020 at 14:27 history asked Ivan Di Liberti CC BY-SA 4.0