Timeline for When is a product of elliptic curves isogenous to the Jacobian of a hyperelliptic curve?
Current License: CC BY-SA 2.5
12 events
when toggle format | what | by | license | comment | |
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Jan 5, 2022 at 5:25 | answer | added | Harun Kir | timeline score: 3 | |
Nov 16, 2018 at 16:03 | vote | accept | Dror Speiser | ||
Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
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Feb 8, 2012 at 22:03 | answer | added | Yuri Zarhin | timeline score: 14 | |
Aug 11, 2010 at 0:42 | comment | added | JSE | By the way, the strategy of Gouvea, Mazur, Rubin, Silverberg for generating lots of quadratic twists of high rank is to find a hyperelliptic curve C on E^r (whose Jacobian thus has E^r as an isogeny quotient.) Then the presence of lots of points on C over quadratic fields (plus some care about linear independence under specialization) shows that E acquires rank at least r over lots of quadratic fields. | |
Aug 10, 2010 at 21:43 | answer | added | JSE | timeline score: 7 | |
Aug 10, 2010 at 16:42 | answer | added | Francesco Polizzi | timeline score: 2 | |
Aug 10, 2010 at 13:50 | comment | added | David Hansen | A nice example due to Jacobi: the Jacobian of $y^2=x(1-x)(1+ax)(1+bx)(1-abx)$ is a product of elliptic curves. | |
Aug 10, 2010 at 11:53 | answer | added | David Lehavi | timeline score: 3 | |
Aug 10, 2010 at 8:00 | answer | added | Dan Petersen | timeline score: 9 | |
Aug 10, 2010 at 7:12 | answer | added | damiano | timeline score: 8 | |
Aug 9, 2010 at 23:28 | history | asked | Dror Speiser | CC BY-SA 2.5 |