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Nov 11, 2021 at 18:48 vote accept Filip
Nov 11, 2021 at 18:48 vote accept Filip
Nov 11, 2021 at 18:48
Feb 12, 2020 at 19:00 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jan 13, 2020 at 17:18 answer added YHBKJ timeline score: 1
Jan 13, 2020 at 13:10 comment added Filip ++ The fact that makes me think this surjectivity to be true in these ADE plumbings examples is that the rank of $SH^i(M)$ is exactly the sum of the ranks of $SH^i(T^*S^2)$, summing by all components of skeleton, for all $i\in \mathbb{Z}$, hence one may think that Viterbo restrictions are sending different subspaces of $SH^*(M)$ isomorphically to $SH^*$ of Weinstein neighborhoods of different spheres.
Jan 12, 2020 at 22:34 comment added Filip Hmm, that is true -- maybe I should be a bit more restrictive, then. I had in mind a setup of holomorphic symplectic manifold $M$ with a Lagrangian skeleton $L$ which is a holomorphic projective variety. Its irreducible components $L_i$ are exact holomorphic Lagrangians, if smooth. In particular, the ambient M could be even hyperkahler, e.g. ADE plumbings of $T^*S^2$. Here the skeleta are ADE trees of Lagrangian $S^2$-spheres, and I think (though I did not prove) that this surjectivity statement is true for those spheres.
Jan 12, 2020 at 19:55 comment added Mohammed Abouzaid This is already false for the inclusion of a circle in a punctured genus 1 surface. What kind of condition do you have in mind?
Jan 12, 2020 at 18:08 history asked Filip CC BY-SA 4.0