Timeline for Fourier transform derivation from Laurent series
Current License: CC BY-SA 4.0
18 events
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Jan 9, 2020 at 16:16 | vote | accept | user740171 | ||
Jan 9, 2020 at 16:16 | comment | added | user740171 | Thank you for your help. | |
Jan 9, 2020 at 15:30 | comment | added | Carlo Beenakker | you are correct, $1/N$ it is. | |
Jan 9, 2020 at 15:29 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jan 9, 2020 at 15:02 | comment | added | user740171 | I did the calculations myself and in the last identity in your answer i did not obtain 1/2π multiplier but i obtained 1/N instead. Am I mistaken ? | |
Jan 9, 2020 at 12:16 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jan 9, 2020 at 12:04 | comment | added | user740171 | Thank you for your response. Isn't it z^(n-1) rather than x^(z-1) in the integral ?? | |
Jan 9, 2020 at 11:21 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jan 9, 2020 at 9:58 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jan 9, 2020 at 9:48 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jan 8, 2020 at 22:18 | comment | added | user740171 | That's right sir, thank you. The CTFT case seems to be closed. After the DFT case is closed I'll mark my question answered. What can we say about the DFT case ? | |
Jan 8, 2020 at 22:03 | comment | added | Carlo Beenakker | Isn’t that what we do when we approximate an integral by a Riemann sum? The approximation becomes more and more accurate as the discretization interval t/T becomes smaller and smaller. | |
Jan 8, 2020 at 21:54 | comment | added | user740171 | n is a countable number, the sum has countably infinite elements in it. However an integral is performed on real numbers which are uncountably infinite. How can we do that transition from countably infinite numbers to uncountably infinite numbers ? Is it just an approximation ? | |
Jan 8, 2020 at 21:14 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jan 8, 2020 at 21:07 | history | undeleted | Carlo Beenakker | ||
Jan 8, 2020 at 21:07 | history | edited | Carlo Beenakker | CC BY-SA 4.0 |
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Jan 8, 2020 at 21:01 | history | deleted | Carlo Beenakker | via Vote | |
Jan 8, 2020 at 21:01 | history | answered | Carlo Beenakker | CC BY-SA 4.0 |