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Jan 7, 2020 at 14:24 history closed abx
Carlo Beenakker
David Handelman
user44191
Alexandre Eremenko
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Jan 7, 2020 at 11:33 answer added Bazin timeline score: 1
Jan 7, 2020 at 11:31 comment added Carlo Beenakker there is really no hope for a compact closed-form expression; if some of your parameters are small, you might exploit that, but otherwise why not just evaluate the integral numerically over the desired interval?
Jan 7, 2020 at 10:44 comment added Nemo There is simplified form of the roots of the cubic equation that might help en.wikibooks.org/wiki/Trigonometry/…
Jan 7, 2020 at 10:35 comment added Nemo Yes, that's what I meant.
Jan 7, 2020 at 10:22 comment added Richard @Nemo Should I divide the numerator by the cubic polynomial in the denominator? Otherwise, the degree of the denominator is more than the numerator.
Jan 7, 2020 at 10:20 review Close votes
Jan 7, 2020 at 14:24
Jan 7, 2020 at 9:56 comment added Nemo You can start by reducing the degree of the numerator using polynomial division.
Jan 7, 2020 at 9:25 review First posts
Jan 7, 2020 at 9:29
Jan 7, 2020 at 9:21 history asked Richard CC BY-SA 4.0