Skip to main content
Notice removed Draw attention by mark
Bounty Ended with Carlo Beenakker's answer chosen by mark
Notice added Draw attention by mark
Bounty Started worth 50 reputation by mark
Rollback to Revision 6
Source Link
Carlo Beenakker
  • 188.2k
  • 18
  • 448
  • 651

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi d\phi}}=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi d\phi}}\,.$$

I$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi }}d\phi=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi }}d\phi\,.$$ I need it as part of a paper on Legendre's proof of the "third singular modulus."

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi d\phi}}=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi d\phi}}\,.$$

I need it as part of a paper on Legendre's proof of the "third singular modulus."

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi }}d\phi=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi }}d\phi\,.$$ I need it as part of a paper on Legendre's proof of the "third singular modulus."

added 2 characters in body
Source Link
mark
  • 153
  • 7

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi }}d\phi=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi }}d\phi\,.$$ I$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi d\phi}}=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi d\phi}}\,.$$

I need it as part of a paper on Legendre's proof of the "third singular modulus."

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi }}d\phi=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi }}d\phi\,.$$ I need it as part of a paper on Legendre's proof of the "third singular modulus."

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi d\phi}}=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi d\phi}}\,.$$

I need it as part of a paper on Legendre's proof of the "third singular modulus."

Rollback to Revision 4
Source Link
Carlo Beenakker
  • 188.2k
  • 18
  • 448
  • 651

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{3^{\frac{1}{4}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi }}d\phi=\int_0^{\arctan\frac{1}{3^{\frac{1}{4}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi }}d\phi\,.$$$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi }}d\phi=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi }}d\phi\,.$$ I need it as part of a paper on Legendre's proof of the "third singular modulus."

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{3^{\frac{1}{4}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi }}d\phi=\int_0^{\arctan\frac{1}{3^{\frac{1}{4}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi }}d\phi\,.$$ I need it as part of a paper on Legendre's proof of the "third singular modulus."

I would like a direct change of variable proof of the identity

$$\int_0^{\arctan\frac{\sqrt{2}}{\sqrt{\sqrt{3}}}} \frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^2\phi }}d\phi=\int_0^{\arctan\frac{1}{\sqrt{\sqrt{3}}}}\frac{1}{\sqrt{1-\frac{2+\sqrt{3}}{4}\sin^22\phi }}d\phi\,.$$ I need it as part of a paper on Legendre's proof of the "third singular modulus."

deleted 9 characters in body
Source Link
mark
  • 153
  • 7
Loading
edited body
Source Link
mark
  • 153
  • 7
Loading
Several changes in the integrand to bring out the fraction
Source Link
mark
  • 153
  • 7
Loading
I put parentheses around an upper limit of integration and put "2\phi" in place of "\2phi" in the second integral. I removed the equal sign after the final integral
Source Link
mark
  • 153
  • 7
Loading
Source Link
mark
  • 153
  • 7
Loading