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Dec 27, 2019 at 18:52 comment added user64494 Yes, the command of Mathematica Simplify[%, Assumptions -> n > 0 && n \ [Element] Integers && \ [Eta] > 0] performs $$\frac{e^{-\frac{\eta ^2}{2}} \eta }{\sqrt{2 \pi } n} .$$
Dec 27, 2019 at 12:22 comment added CPW The answer seems can be simplified further as $ \frac{e^{-\frac{\eta^2}{2}} \eta}{\sqrt{2 \pi} \frac{1}{n}$
Dec 27, 2019 at 12:13 comment added CPW Thanks you so much! Can you send me your address so that I can acknowledge you properly?
Dec 27, 2019 at 10:39 history answered user64494 CC BY-SA 4.0