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Dec 23, 2019 at 19:36 comment added Sam Hopkins Related question which you might possibly be interested in: mathoverflow.net/questions/4982/look-into-delzant-polytope. In particular, note the answer of Joel Fine explaining that the Delzant condition is the same as saying that each vertex can be taken to the positive orthant model by some element of $GL(n,\mathbb{Z})$.
Dec 23, 2019 at 19:28 history asked BrianT CC BY-SA 4.0