Timeline for Is every locally free module of rank $1$ over a commutative ring concretely invertible?
Current License: CC BY-SA 4.0
11 events
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Dec 26, 2019 at 22:37 | vote | accept | Georges Elencwajg | ||
Dec 26, 2019 at 20:44 | answer | added | darx | timeline score: 10 | |
Dec 24, 2019 at 23:41 | comment | added | Georges Elencwajg | @Martin Brandenburg. No, I didn't. | |
Dec 24, 2019 at 20:23 | comment | added | Martin Brandenburg | Since the result holds over noetherian bases, the obvious idea would be to make a noetherian approximation (write $A$ as a colimit of its f.g. subrings) and use that $P$ is f.p. Did you try that? | |
Dec 24, 2019 at 19:37 | history | edited | Georges Elencwajg | CC BY-SA 4.0 |
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Dec 22, 2019 at 9:56 | history | edited | Georges Elencwajg | CC BY-SA 4.0 |
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Dec 22, 2019 at 1:07 | answer | added | Jesse Elliott | timeline score: 6 | |
Dec 22, 2019 at 0:07 | history | edited | Georges Elencwajg | CC BY-SA 4.0 |
added 214 characters in body
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Dec 21, 2019 at 23:58 | history | edited | Georges Elencwajg | CC BY-SA 4.0 |
added 214 characters in body
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Dec 21, 2019 at 23:48 | history | edited | Georges Elencwajg | CC BY-SA 4.0 |
added 214 characters in body
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Dec 21, 2019 at 22:08 | history | asked | Georges Elencwajg | CC BY-SA 4.0 |