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Dec 30, 2019 at 10:29 answer added Sam Nead timeline score: 3
Dec 30, 2019 at 5:07 comment added Lee Mosher Someone should turn this discussion into an answer.
Dec 30, 2019 at 3:18 history edited Jeffrey Rolland CC BY-SA 4.0
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Dec 20, 2019 at 22:45 history edited Jeffrey Rolland CC BY-SA 4.0
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Dec 20, 2019 at 22:39 comment added Jeffrey Rolland @YCor Edited into OP
Dec 20, 2019 at 22:38 history edited Jeffrey Rolland CC BY-SA 4.0
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Dec 20, 2019 at 22:09 comment added Jeffrey Rolland @DannyRuberman Wow, that's awesome, thank you! I'm actually going to take a fiber bundle with a torus as the base manifold and need the total space to be at least 6-dim'l at some point, so I could just use a 3-dim'l torus or a 2-dim'l torus and a higher-dim'l example of what you just suggested; it's kind-of "six of one, half a dozen of another" to me at this point. However, modulo the dimension of the manifold, this is exactly what I needed, so thank you
Dec 20, 2019 at 19:00 comment added Danny Ruberman See section 2.3 of the Boileau-Zieschang paper; you'll need to compute the Seifert invariants first. You can find the answer in section 3.5.1 of Saveliev's book, Invariants for homology 3-spheres. Did you only care about the 3-dimensional case? My comment above gives examples for dim = 0 mod 3, but probably there are ways to do dim = 1 or 2 mod 3.
Dec 20, 2019 at 17:38 comment added Jeffrey Rolland @DannyRuberman Just a finite presentation of the fundamental groups; I'll need that for the construction I'm doing
Dec 20, 2019 at 16:06 comment added Danny Ruberman I think SnapPy is all about hyperbolic manifolds. What are you hoping to learn/compute about those examples using SnapPy?
Dec 20, 2019 at 16:02 comment added Danny Ruberman One more point--there are well-known genus 2 Heegaard splittings (derived from well-known surgery diagrams) for the Brieskorn homology spheres with 3 exceptional fibers. See eg Boileau-Zieschang [link] (numdam.org/article/AST_1988__163-164__247_0.pdf)
Dec 20, 2019 at 16:00 comment added Jeffrey Rolland Thanks so much for the responses. If I may "go to the well" one more time, how may I specify a Brieskorn homology sphere in SnapPy?
Dec 20, 2019 at 15:54 comment added HJRW @DannyRuberman — of course. I said that $\mathbb{Z}$ is “the best you can do”, because the OP was hoping for $\mathbb{Z}/2$.
Dec 20, 2019 at 15:52 comment added Danny Ruberman @HJRW Perhaps you mean that the center (if non-trivial) must contain $\mathbb{Z}$? Since the OP didn't specify the dimension one could take products of Seifert fibered spaces. This produces examples in dimension $3n$ with center $\mathbb{Z}^n$.
Dec 20, 2019 at 15:46 comment added Jeffrey Rolland @HJRW Thanks so much for the Brieskorn homology spheres examples! I really appreciate it!
Dec 20, 2019 at 15:44 comment added Jeffrey Rolland @HJRW That's right, and the hyperbolic ones, at least (I think?), can't have a $\mathbb{Z} \times \mathbb{Z}$ or higher rank free Abelian group as a subgroup; I had looked up both those facts last night but forgot them. It's truly $\mathbb{Z}$ or nothing, thanks.
Dec 20, 2019 at 15:38 comment added HJRW The fundamental groups of aspherical manifolds are always torsion free for homological reasons, so a centre of $\mathbb{Z}$ is the best you can do.
Dec 20, 2019 at 15:32 comment added YCor Glossary: $G$ superperfect means $H_1(G,\mathbf{Z})=H_2(G,\mathbf{Z})=0$.
Dec 20, 2019 at 15:32 comment added HJRW In every dimension, the fundamental group of a hyperbolic manifold has trivial centre. There are no examples of what you want in dimension 2, but in dimension 3, there are the Brieskorn homology spheres $\Sigma(p,q,r)$ for $1/p+1/q+1/r <1$. These are aspherical homology spheres which are Seifert fibred, so their fundamental groups have centre $\mathbb{Z}$.
Dec 20, 2019 at 15:32 history edited YCor CC BY-SA 4.0
removed capitals from title, fixed typos
Dec 20, 2019 at 15:17 history asked Jeffrey Rolland CC BY-SA 4.0