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Timeline for A computation of ramification

Current License: CC BY-SA 2.5

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Aug 8, 2010 at 17:43 comment added Dror Speiser On a different level, for any Dedekind domain $R$, with 2 and $\epsilon$ units, $R[\sqrt{\epsilon}]$ is integrally closed. This is clear from the minimal polynomial of $a+b\sqrt{\epsilon}$. Applying this twice we get the specific example.
Aug 8, 2010 at 16:01 comment added H. Hasson ...and I just found the problem in my roundabout way. Thanks!
Aug 8, 2010 at 15:18 vote accept H. Hasson
Aug 8, 2010 at 10:39 comment added Qing Liu It is smooth over $D$ (either directly using Jacobian criterion or because it is étale over $V$ which is smooth over $D$). As $D$ is regular, $U$ is regular, hence integrally closed.
Aug 7, 2010 at 22:36 comment added H. Hasson Maybe this is a trivial matter, but I don't see why D[y,z, 1/f(y)]/(z^n-f(y)) would be integrally closed.
Aug 7, 2010 at 21:58 history answered Qing Liu CC BY-SA 2.5