Timeline for If $f(x_1,x_2)=f(x_2,x_1)$, $f(x_1,x_2)=\sum_k \lambda_k f_k(x_1)f_k(x_2)$? [closed]
Current License: CC BY-SA 4.0
9 events
when toggle format | what | by | license | comment | |
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Dec 20, 2019 at 17:07 | history | closed |
Francois Ziegler user44191 ARG Max Horn Alex M. |
Needs details or clarity | |
Dec 19, 2019 at 12:40 | review | Close votes | |||
Dec 20, 2019 at 17:07 | |||||
Dec 19, 2019 at 12:20 | comment | added | Francois Ziegler | In what sense is the series’ convergence supposed to be? | |
Dec 19, 2019 at 12:03 | answer | added | Iosif Pinelis | timeline score: 5 | |
Dec 19, 2019 at 11:38 | comment | added | Mateusz Kwaśnicki | If $f$ is the kernel of, say, a Hilbert–Schmidt operator on $L^2(dm)$, then of course yes. In general, the answer depends on your notion of convergence of the series, but most likely it is "not necessarily". If I am not mistaken, $m(dx) = e^{-x^2} dx$ and $f(x,y) = e^{x^2+y^2}$ is a simple counter-example under reasonable notions of convergence. | |
Dec 19, 2019 at 10:02 | comment | added | mathmetricgeometry | @BenMcKay: The conditions given above show that it's square integrable | |
Dec 19, 2019 at 9:37 | comment | added | Ben McKay | Do you want these $f_k$ to be square integrable functions? | |
Dec 19, 2019 at 9:34 | comment | added | Anthony Quas | Ummm. Are there any hypotheses you’d like us to know about? | |
Dec 19, 2019 at 8:43 | history | asked | mathmetricgeometry | CC BY-SA 4.0 |