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Dec 19, 2019 at 22:46 vote accept user142929
Dec 19, 2019 at 22:36 answer added Joel Moreira timeline score: 1
Dec 19, 2019 at 19:34 comment added user142929 Many thanks for your feedback, the differences $LHS-RHS$ are very small even for the humble segment of my experiments $2700\leq n\leq 50000$, thus I suspect that maybe some user can to find a counterexample, but the best way to refute the conjecture is provide a convincing reasoning as yours. Thus I am going to wait if there is some answer, feel free to add yourself reasoning as an answer. Many thanks @JoelMoreira
Dec 19, 2019 at 16:46 comment added Joel Moreira Hm, apparently $p_n/(n\log n)$ decays to $1$ rather slowly (it behaves like $1+\frac{\log\log n}{\log n}$), so I take back my guess that an improvement of PNT will show that (2) is false.
Dec 19, 2019 at 16:15 comment added Joel Moreira Replacing $p_n$ with $n\log n$ in (2) yields a false inequality for all large $n$. I'm guessing that some improved form of the prime number theorem may imply that (2) is false.
Dec 19, 2019 at 13:21 comment added user142929 Due the form of the functions $\lambda(n)$ and $\mu(n)$ that I've choosen by experimenting, the inequality $(2)$ can be written as $$e^{e^{A(n)}}>n^{n^{G(n)}},\text{ for integers } n\geq 2700$$ where the exponent $A(n)$ denotes the arithmetic mean $A(\underbrace{1,\ldots,1}_{n\text{ ones}},p_{n+1})=\frac{n+p_{n+1}}{n+1}$ and $G(n)$ denotes the geometric mean $G(\underbrace{1,\ldots,1}_{n-1\text{ ones}},p_{n})=\sqrt[n]{p_{n}}$. This is just to emphasize that my inequality is a comparison of means, in the same way that Firoozbakht's conjecture can be interpreted in terms of geometric means
Dec 18, 2019 at 23:40 comment added user142929 Also is welcome comments about if my inequality $(2)$ is interesting or if there are similar inequalities in the literature.
Dec 18, 2019 at 21:19 comment added user142929 I think that the idea is thus if it is possible to prove or refute the inequality $(2)$ for some $n_0>2700$ using the explicit inequalities for primes, since I cann't find a counterexample. Feel free to add comments/critics about this question, I'm waiting your feedback. Thank you very much.
Dec 18, 2019 at 10:44 history edited user142929 CC BY-SA 4.0
Fixed a typo in the code.
Dec 18, 2019 at 10:26 history edited user142929 CC BY-SA 4.0
Grammar
Dec 18, 2019 at 10:17 history asked user142929 CC BY-SA 4.0