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Aug 7, 2010 at 22:39 comment added BCnrd Dear Qing: yep.
Aug 7, 2010 at 22:09 comment added Qing Liu If $S$ is Noetherian affine and normal, and $X$ is normal, as $O(X_U)=O(U)$, then Zariski's extension theorem imply that $O(X)=O(S)$. I think this is reason why BCnrd said "try non-normal counterexample". The problem I think is to find $X$ flat over $S$.
Aug 7, 2010 at 21:15 history edited Angelo CC BY-SA 2.5
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Aug 7, 2010 at 17:18 history edited Angelo CC BY-SA 2.5
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Aug 7, 2010 at 16:28 comment added Angelo Oops sorry, I had missed the comment.
Aug 7, 2010 at 16:19 comment added BCnrd Dear Angelo: The OP made the comment below the question that he only actually has properness over a dense open in $S$. So unfortunately the usual cohomological tools seem to not apply. I hope the OP will follow my request to please revise the question to include the hypotheses desired (and to make clear if U is quasi-compact over S, schematically or just topologically dense, etc.).
Aug 7, 2010 at 16:11 history answered Angelo CC BY-SA 2.5