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Dec 14, 2019 at 15:44 comment added Sam Hopkins As Darij says, the exact same definitions work for bounded entries; it's just that if the entries are bounded by $n$, then we only have $n-1$ involutions $BK_i$ for $1\leq i \leq n-1$.
Dec 14, 2019 at 15:43 comment added darij grinberg Have you read the original paper? I think it makes it pretty clear why the involution doesn't "overflow" the entries ("column $j$ has a $k+1$ but no $k$" shows that $k+1$ is not out of bound).
Dec 14, 2019 at 15:39 history asked Jianrong Li CC BY-SA 4.0