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Coda:

Projective transformations of $\mathbb{C}P^{n}$ act on the solutions of the equation $L\bar L=I$, respectively $L\bar L=-I$, by transformations $L\mapsto U^{-1}L\bar U$, where $U$ is an invertible complex $(n+1)\times (n+1)$ matrix. It remains to show that each solution can be transformed to $I$ and $J=\left(\begin{smallmatrix} 0 & -I\\ I & 0\end{smallmatrix}\right)$ respectively, i.e., each matrix $L$ satisfying $L\bar L=I$ (respectively, $L\bar L=-I$) has form $L=U^{-1}\bar U$ (respectively, $L=U^{-1}J\bar U$ ) for some invertible matrix $U$.

If $L\bar L=I$, then take $a\in\mathbb{R}$ such that $-e^{2ia}$ is not an eigenvalue of $\bar L$. Then $U:=e^{ia}I+e^{-ia}\bar L$ is the required invertible matrix because $UL=(e^{ia}I+e^{-ia}\bar L)L=e^{ia}L+e^{-ia}I=\bar U$ by the equation $\bar LL=L\bar L=I$.

If $L\bar L=-I$, then take $a\in\mathbb{R}$ such that $e^{2ia}$ is not an eigenvalue of $J\bar L$. Then $U:=e^{ia}J+e^{-ia}\bar L$ is the required matrix: $UL=(e^{ia}J+e^{-ia}\bar L)L=e^{ia}JL+e^{-ia}J\bar J=J\bar U$ because $\bar LL=L\bar L=-I=J\bar J$.

Coda (Lemma 11 from arXiv:2002.01355):

Projective transformations of $\mathbb{C}P^{n}$ act on the solutions of the equation $L\bar L=I$, respectively $L\bar L=-I$, by transformations $L\mapsto U^{-1}L\bar U$, where $U$ is an invertible complex $(n+1)\times (n+1)$ matrix. It remains to show that each solution can be transformed to $I$ and $J=\left(\begin{smallmatrix} 0 & -I\\ I & 0\end{smallmatrix}\right)$ respectively, i.e., each matrix $L$ satisfying $L\bar L=I$ (respectively, $L\bar L=-I$) has form $L=U^{-1}\bar U$ (respectively, $L=U^{-1}J\bar U$ ) for some invertible matrix $U$.

If $L\bar L=I$, then take $a\in\mathbb{R}$ such that $-e^{2ia}$ is not an eigenvalue of $\bar L$. Then $U:=e^{ia}I+e^{-ia}\bar L$ is the required invertible matrix because $UL=(e^{ia}I+e^{-ia}\bar L)L=e^{ia}L+e^{-ia}I=\bar U$ by the equation $\bar LL=L\bar L=I$.

If $L\bar L=-I$, then take $a\in\mathbb{R}$ such that $e^{2ia}$ is not an eigenvalue of $J\bar L$. Then $U:=e^{ia}J+e^{-ia}\bar L$ is the required matrix: $UL=(e^{ia}J+e^{-ia}\bar L)L=e^{ia}JL+e^{-ia}J\bar J=J\bar U$ because $\bar LL=L\bar L=-I=J\bar J$.

Coda:

Projective transformations of $\mathbb{C}P^{n}$ act on the solutions of the equations $L\bar L=\pm I$ by transformations $L\mapsto U^{-1}L\bar U$, where $U$ is an invertible complex $(n+1)\times (n+1)$ matrix. It remains to show that each solution can be transformed to $I$ and $J=\left(\begin{smallmatrix} 0 & -I\\ I & 0\end{smallmatrix}\right)$ respectively, i.e., each matrix $L$ satisfying $L\bar L=I$ (respectively, $L\bar L=-I$) has form $L=U^{-1}\bar U$ (respectively, $L=U^{-1}J\bar U$ ) for some invertible matrix $U$.

If $L\bar L=I$, then take $a\in\mathbb{R}$ such that $-e^{2ia}$ is not an eigenvalue of $\bar L$. Then $U:=e^{ia}I+e^{-ia}\bar L$ is the required invertible matrix because $UL=(e^{ia}I+e^{-ia}\bar L)L=e^{ia}L+e^{-ia}I=\bar U$ by the equation $\bar LL=L\bar L=I$.

If $L\bar L=-I$, then take $a\in\mathbb{R}$ such that $e^{2ia}$ is not an eigenvalue of $J\bar L$. Then $U:=e^{ia}J+e^{-ia}\bar L$ is the required matrix: $UL=(e^{ia}J+e^{-ia}\bar L)L=e^{ia}JL+e^{-ia}J\bar J=J\bar U$ because $\bar LL=L\bar L=-I=J\bar J$.

Coda:

Projective transformations of $\mathbb{C}P^{n}$ act on the solutions of the equation $L\bar L=I$, respectively $L\bar L=-I$, by transformations $L\mapsto U^{-1}L\bar U$, where $U$ is an invertible complex $(n+1)\times (n+1)$ matrix. It remains to show that each solution can be transformed to $I$ and $J=\left(\begin{smallmatrix} 0 & -I\\ I & 0\end{smallmatrix}\right)$ respectively, i.e., each matrix $L$ satisfying $L\bar L=I$ (respectively, $L\bar L=-I$) has form $L=U^{-1}\bar U$ (respectively, $L=U^{-1}J\bar U$ ) for some invertible matrix $U$.

If $L\bar L=I$, then take $a\in\mathbb{R}$ such that $-e^{2ia}$ is not an eigenvalue of $\bar L$. Then $U:=e^{ia}I+e^{-ia}\bar L$ is the required invertible matrix because $UL=(e^{ia}I+e^{-ia}\bar L)L=e^{ia}L+e^{-ia}I=\bar U$ by the equation $\bar LL=L\bar L=I$.

If $L\bar L=-I$, then take $a\in\mathbb{R}$ such that $e^{2ia}$ is not an eigenvalue of $J\bar L$. Then $U:=e^{ia}J+e^{-ia}\bar L$ is the required matrix: $UL=(e^{ia}J+e^{-ia}\bar L)L=e^{ia}JL+e^{-ia}J\bar J=J\bar U$ because $\bar LL=L\bar L=-I=J\bar J$.

Coda:

Projective transformations of $\mathbb{C}P^{n}$ act on the solutions of the equations $L\bar L=\pm I$ by transformations $L\mapsto U^{-1}L\bar U$, where $U$ is an invertible complex $(n+1)\times (n+1)$ matrix. It remains to show that each solution can be transformed to either $I$ or $J=\left(\begin{smallmatrix} 0 & -I\\ I & 0\end{smallmatrix}\right)$, i.e., each matrix $L$ satisfying $L\bar L=I$ (respectively, $L\bar L=-I$) has form $L=U^{-1}\bar U$ (respectively, $L=U^{-1}J\bar U$ ) for some invertible matrix $U$.

If $L\bar L=I$, then take $a\in\mathbb{R}$ such that $-e^{2ia}$ is not an eigenvalue of $\bar L$. Then $U:=e^{ia}I+e^{-ia}\bar L$ is the required invertible matrix because $UL=(e^{ia}I+e^{-ia}\bar L)L=e^{ia}L+e^{-ia}I=\bar U$ by the equation $\bar LL=L\bar L=I$.

If $L\bar L=-I$, then take $a\in\mathbb{R}$ such that $e^{2ia}$ is not an eigenvalue of $J\bar L$. Then $U:=e^{ia}J+e^{-ia}\bar L$ is the required matrix: $UL=(e^{ia}J+e^{-ia}\bar L)L=e^{ia}JL+e^{-ia}J\bar J=J\bar U$ because $\bar LL=L\bar L=-I=J\bar J$.

Coda:

Projective transformations of $\mathbb{C}P^{n}$ act on the solutions of the equations $L\bar L=\pm I$ by transformations $L\mapsto U^{-1}L\bar U$, where $U$ is an invertible complex $(n+1)\times (n+1)$ matrix. It remains to show that each solution can be transformed to $I$ and $J=\left(\begin{smallmatrix} 0 & -I\\ I & 0\end{smallmatrix}\right)$ respectively, i.e., each matrix $L$ satisfying $L\bar L=I$ (respectively, $L\bar L=-I$) has form $L=U^{-1}\bar U$ (respectively, $L=U^{-1}J\bar U$ ) for some invertible matrix $U$.

If $L\bar L=I$, then take $a\in\mathbb{R}$ such that $-e^{2ia}$ is not an eigenvalue of $\bar L$. Then $U:=e^{ia}I+e^{-ia}\bar L$ is the required invertible matrix because $UL=(e^{ia}I+e^{-ia}\bar L)L=e^{ia}L+e^{-ia}I=\bar U$ by the equation $\bar LL=L\bar L=I$.

If $L\bar L=-I$, then take $a\in\mathbb{R}$ such that $e^{2ia}$ is not an eigenvalue of $J\bar L$. Then $U:=e^{ia}J+e^{-ia}\bar L$ is the required matrix: $UL=(e^{ia}J+e^{-ia}\bar L)L=e^{ia}JL+e^{-ia}J\bar J=J\bar U$ because $\bar LL=L\bar L=-I=J\bar J$.