Skip to main content

Timeline for A question on Okounkov bodies

Current License: CC BY-SA 4.0

2 events
when toggle format what by license comment
Dec 8, 2019 at 23:44 comment added Devlin Mallory I’ll try to return to answer the example you gave, but just a brief note: you won’t be able to get away just by working with global sections of some ample $D$, since such a divisor need not have any sections. You can probably take some sufficiently ample multiple of $D$ and then divide.
Dec 8, 2019 at 15:51 history asked user125056 CC BY-SA 4.0