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Dec 10, 2019 at 12:46 comment added Delio Mugnolo Yes, I know that my operator is contractive on all $L^p$-spaces. My question really was about the way it acts on continuous functions.
Dec 9, 2019 at 15:53 comment added Bazin @DelioMugnolo Do you know if your operator is $L^p$ bounded for $p\in (1,+\infty)$? On the other hand, I believe that the condition on the essential supremum is necessary for $L^\infty$ boundedness, at least in an Euclidean framework with the Lebesgue measure.
Dec 8, 2019 at 18:33 comment added Delio Mugnolo Thanks, but the question is related to a specific application I have in mind. I already know by other means that the operator is bounded on $L^2$; what I want is to deduce from properties of its kernel that it's also bounded on $BUC$ or $C_0$.
Dec 7, 2019 at 17:15 history answered Bazin CC BY-SA 4.0