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Dec 10, 2019 at 18:07 vote accept Asvin
Dec 6, 2019 at 16:27 comment added SashaP The quotient $R/\mathfrak{p}^n$ should probably be replaced by $R/p^n$ since the ideal $\mathfrak{p}$ is equal to all of its powers: $\mathfrak{p}=\mathfrak{p}^2=\dots$.
Dec 6, 2019 at 16:26 answer added SashaP timeline score: 6
Dec 6, 2019 at 9:43 comment added Filippo Alberto Edoardo If you're happy to assume that $\mathcal{A}$ is ordinary, then $E_n,E_n'$ are also ordinary for all $n$ and you can apply Serre--Tate lifting theorem, I believe.
Dec 6, 2019 at 3:18 history edited Asvin CC BY-SA 4.0
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Dec 5, 2019 at 18:02 history asked Asvin CC BY-SA 4.0