Timeline for Interpolating asymptotic expression for logarithm of middle binomial sums
Current License: CC BY-SA 4.0
17 events
| when toggle format | what | by | license | comment | |
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| Jan 3, 2020 at 23:29 | answer | added | skbmoore | timeline score: 1 | |
| Dec 17, 2019 at 4:12 | history | edited | VS. | CC BY-SA 4.0 |
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| Dec 17, 2019 at 3:57 | history | edited | VS. | CC BY-SA 4.0 |
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| Dec 17, 2019 at 2:08 | history | edited | VS. | CC BY-SA 4.0 |
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| Dec 3, 2019 at 18:27 | answer | added | Marcus M | timeline score: 1 | |
| Dec 3, 2019 at 13:46 | history | edited | VS. | CC BY-SA 4.0 |
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| Dec 3, 2019 at 13:19 | comment | added | Wolfgang | "At every i" should probably be "for every k". | |
| Dec 3, 2019 at 12:52 | history | edited | VS. | CC BY-SA 4.0 |
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| Dec 3, 2019 at 12:47 | history | edited | VS. | CC BY-SA 4.0 |
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| Dec 3, 2019 at 12:43 | comment | added | VS. | So it is fair to say at $\gamma>\frac12$ we have $2n\ln2 -o(1)$? | |
| Dec 3, 2019 at 12:37 | comment | added | Brendan McKay | I don't get the "$1-\gamma$" term as it subtracts at most one term from each end of the sum. Leaving that aside, for $\gamma\gt \frac12$ you have $2n\ln 2$ and for smaller $\gamma$ you have the normal approximation of the binomial distribution. | |
| Dec 3, 2019 at 12:23 | history | edited | VS. | CC BY-SA 4.0 |
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| Dec 3, 2019 at 11:01 | comment | added | Max Alekseyev | Bounds from mathoverflow.net/q/55585/7076 may be helpful here. | |
| Dec 3, 2019 at 8:16 | comment | added | VS. | This is the first time I am hearing Wilf Zeilberger. Perhaps you can post full answer? | |
| Dec 3, 2019 at 7:20 | comment | added | Zubin Mukerjee | On a bit of a tangent, but have you tried to use Wilf Zeilberger to generate any equivalent expressions for your $S(k,2n)$? | |
| Dec 3, 2019 at 7:09 | history | edited | VS. | CC BY-SA 4.0 |
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| Dec 3, 2019 at 7:01 | history | asked | VS. | CC BY-SA 4.0 |