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Dec 3, 2019 at 4:58 history became hot network question
Dec 3, 2019 at 0:32 vote accept CommunityBot
Dec 3, 2019 at 0:30 answer added Connor Mooney timeline score: 16
Dec 3, 2019 at 0:18 answer added fedja timeline score: 18
Dec 2, 2019 at 23:44 comment added user69109 @NateEldredge correct, sorry for the typo. It is the Sobolev space.
Dec 2, 2019 at 23:43 history edited user69109 CC BY-SA 4.0
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Dec 2, 2019 at 23:42 comment added Nate Eldredge @AlexandreEremenko: I presume it's Sobolev space, but it probably really should be $H^3$.
Dec 2, 2019 at 23:42 comment added Alexandre Eremenko What is $H^2(R)$? Hardy space?
Dec 2, 2019 at 22:42 comment added Math604 might want to try scaling argument first to see if its even possible... take $ f $ smooth and compactly supported and then assume inequality holds and put $ f_\lambda(x)= f(\lambda x)$ and vary $ \lambda>0$ and see if you get contradiction...
Dec 2, 2019 at 22:01 history edited user69109 CC BY-SA 4.0
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Dec 2, 2019 at 21:30 history edited user69109 CC BY-SA 4.0
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Dec 2, 2019 at 21:20 history edited user69109 CC BY-SA 4.0
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Dec 2, 2019 at 20:55 history asked user69109 CC BY-SA 4.0